The reaction,which forms nitric oxide $(NO)$,is:
- A$C$ and $O_2$
- B$Cu$ and $N_2O$
- C$Na$ and $NH_3$
- D$Cu$ and $HNO_3$ (dilute)
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Similar Questions
The number of bridged oxygen atoms present in compound $B$ formed from the following reactions is
$Pb(NO_3)_2 \xrightarrow{673 \ K} A + PbO + O_2$
$A \xrightarrow{\text{Dimerise}} B$
$Pb(NO_3)_2 \xrightarrow{673 \ K} A + PbO + O_2$
$A \xrightarrow{\text{Dimerise}} B$
$NH_3 + O_2 \xrightarrow[\Delta]{Pt} A + H_2O$ ;
$A + O_2 \to B$ ;
$B + O_2 + H_2O \to C$
$A, B$ and $C$ are:
$A + O_2 \to B$ ;
$B + O_2 + H_2O \to C$
$A, B$ and $C$ are:
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