The reactance of a capacitor is X_{C}. If the | vedclass

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(C) The capacitive reactance $X_{C}$ is given by the formula $X_{C} = \frac{1}{2 \pi f C}$,where $f$ is the frequency and $C$ is the capacitance.Let t

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$X_{C}/4$

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(C) The capacitive reactance $X_{C}$ is given by the formula $X_{C} = \frac{1}{2 \pi f C}$,where $f$ is the frequency and $C$ is the capacitance.Let the initial reactance be $X_{C} = \frac{1}{2 \pi f C}$.When the frequency $f$ is doubled $(f' = 2f)$ and the capacitance $C$ is doubled $(C' = 2C)$,the new reactance $X_{C}'$ is given by:$X_{C}' = \frac{1}{2 \pi f' C'} = \frac{1}{2 \pi (2f) (2C)}$.$X_{C}' = \frac{1}{4 (2 \pi f C)} = \frac{1}{4} X_{C}$.Therefore,the new reactance is $\frac{X_{C}}{4}$.

The reactance of a capacitor is $X_{C}$. If the frequency and the capacitance are doubled,then the new reactance will be

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