The ratio of the volume of an $Al^{27}$ nucleus to its surface area is (Given,$R_0 = 1.2 \times 10^{-15} \ m$):

  • A
    $2.1 \times 10^{-15} \ m$
  • B
    $1.3 \times 10^{-15} \ m$
  • C
    $0.22 \times 10^{-15} \ m$
  • D
    $1.2 \times 10^{-15} \ m$

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