The ratio of the rate of diffusion of helium | vedclass

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(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.For helium $(He)$ and methane $(CH_4)$,the ratio is given by: $\frac{r_{He}}{r_{CH_4}} = \sqrt{\frac{M_{CH_4}}{M_{He}}}$.The molar mass of methane $(CH_4)$ is $16 \ g/mol$ and helium $(He)$ is $4 \ g/mol$.Substituting the values: $\frac{r_{He}}{r_{CH_4}} = \sqrt{\frac{16}{4}} = \sqrt{4} = 2$.

The ratio of the rate of diffusion of helium and methane under identical conditions of pressure and temperature will be

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