The ratio of specific heat at constant pressure to specific heat at constant volume $(\gamma)$ for a gas is given by $\gamma = 1 + \frac{2}{f}$,where $f$ is the number of degrees of freedom of a molecule of the gas. What is the ratio of $\gamma_{d}$ for a rigid diatomic gas to $\gamma_{m}$ for a monoatomic gas?
- A$\frac{14}{23}$
- B$\frac{25}{21}$
- C$\frac{21}{25}$
- D$\frac{23}{14}$
Explore More
Similar Questions
Match List-$I$ with List-$II$:
List-$I$ List-$II$ $(A)$ $3$ Translational degrees of freedom $(I)$ Monoatomic gases $(B)$ $3$ Translational,$2$ rotational degrees of freedom $(III)$ Rigid diatomic gases $(C)$ $3$ Translational,$2$ rotational and $1$ vibrational degrees of freedom $(IV)$ Non-rigid diatomic gases $(D)$ $3$ Translational,$3$ rotational and more than one vibrational degrees of freedom $(II)$ Polyatomic gases
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ $3$ Translational degrees of freedom | $(I)$ Monoatomic gases |
| $(B)$ $3$ Translational,$2$ rotational degrees of freedom | $(III)$ Rigid diatomic gases |
| $(C)$ $3$ Translational,$2$ rotational and $1$ vibrational degrees of freedom | $(IV)$ Non-rigid diatomic gases |
| $(D)$ $3$ Translational,$3$ rotational and more than one vibrational degrees of freedom | $(II)$ Polyatomic gases |
Choose the correct answer from the options given below:
Write the degree of freedom for a diatomic rigid rotator.
Medium
View SolutionFor a diatomic gas,let $\gamma_1 = \frac{C_p}{C_v}$ for rigid molecules and $\gamma_2 = \frac{C_p}{C_v}$ for diatomic molecules that also have a vibrational mode. Which of the following options is correct? ($C_p$ and $C_v$ are the specific heats of the gas at constant pressure and volume,respectively.)
The total kinetic energy of $1$ mole of oxygen at $27^{\circ} C$ is:
[Use universal gas constant $(R) = 8.31 \ J/mol \cdot K$] (in $J$)
[Use universal gas constant $(R) = 8.31 \ J/mol \cdot K$] (in $J$)
DifficultJEE MAIN 2024
View Solution$500 \text{ g}$ of a diatomic gas is enclosed at a pressure of $10^5 \text{ N m}^{-2}$. The density of the gas is $5 \text{ kg m}^{-3}$. The energy of one mole of the gas due to its thermal motion is [consider the gas molecule as a rigid rotator].
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo