The ratio of mass percentage (w/w) of $C : H$ in a hydrocarbon is $12 : 1$. It has two carbon atoms. The weight (in $g$) of $CO_2(g)$ formed when $3.38 \ g$ of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in $g \ mol^{-1}$,$C : 12, H : 1, O : 16$)

  • A
    $5.68$
  • B
    $11.44$
  • C
    $22.74$
  • D
    $17.05$

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