The range of the function $f(x) = \frac{x}{{1 + \left| x \right|}},\,x \in R,$ is
$R$
$(-1,1)$
$R-\{0\}$
$[-1,1]$
If a function $f(x)$ is such that $f\left( {x + \frac{1}{x}} \right) = {x^2} + \frac{1}{{{x^2}}};$ then $(fof )$ $\sqrt {11} )$ =
Function $f(x)={\left( {1 + \frac{1}{x}} \right)^x}$ then Range of the function f (x) is
If $f(x)$ is a function satisfying $f(x + y) = f(x)f(y)$ for all $x,\;y \in N$ such that $f(1) = 3$ and $\sum\limits_{x = 1}^n {f(x) = 120} $. Then the value of $n$ is
A function $f(x)$ is given by $f(x)=\frac{5^{x}}{5^{x}+5}$, then the sum of the series
$f\left(\frac{1}{20}\right)+f\left(\frac{2}{20}\right)+f\left(\frac{3}{20}\right)+\ldots \ldots+f\left(\frac{39}{20}\right)$ is equal to ....... .