The radius of Germanium (Ge) nuclide is measu | vedclass

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(D) The radius of a nucleus is given by the formula $R = R_{0}A^{1/3}$,where $R_{0}$ is a constant and $A$ is the mass number (number of nucleons).Giv

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$72$

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(D) The radius of a nucleus is given by the formula $R = R_{0}A^{1/3}$,where $R_{0}$ is a constant and $A$ is the mass number (number of nucleons).Given that the radius of $Ge$ is twice the radius of $_{4}^{9}	ext{Be}$,we have $R_{Ge} = 2R_{Be}$.Using the formula,we can write the ratio as $\frac{R_{Ge}}{R_{Be}} = \frac{A_{Ge}^{1/3}}{A_{Be}^{1/3}}$.Substituting the given values: $2 = \left(\frac{A_{Ge}}{9}ight)^{1/3}$.Cubing both sides,we get $2^{3} = \frac{A_{Ge}}{9}$.$8 = \frac{A_{Ge}}{9}$.$A_{Ge} = 8 	imes 9 = 72$.Therefore,the number of nucleons in $Ge$ is $72$.

The radius of Germanium $(Ge)$ nuclide is measured to be twice the radius of $_{4}^{9}\text{Be}$ . The number of nucleons in $Ge$ are

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