The radius of curvature of the convex surface | vedclass

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(D) For a plano-convex lens, the lens maker's formula is given by $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a plano-c

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$+4 \, D$

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(D) For a plano-convex lens, the lens maker's formula is given by $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} ight)$.For a plano-convex lens, $R_1 = R = 15 \, cm$ and $R_2 = \infty$.Substituting the values: $\frac{1}{f} = (1.6 - 1) \left( \frac{1}{15} - \frac{1}{\infty} ight) = 0.6 	imes \frac{1}{15} = \frac{0.6}{15} = \frac{1}{25} \, cm^{-1}$.Thus, the focal length $f = 25 \, cm = 0.25 \, m$.The power of the lens $P$ is given by $P = \frac{1}{f(in \, meters)} = \frac{1}{0.25} = +4 \, D$.

The radius of curvature of the convex surface of a thin plano-convex lens is $15 \, cm$ and the refractive index of its material is $1.6$. The power of the lens will be:

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