The radius and slant height of a conical vess | vedclass

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(C) Given: Radius $(r)$ = $21 \,cm$,Slant height $(l)$ = $29 \,cm$.First,find the height $(h)$ of the cone using the relation $l^2 = r^2 + h^2$.$h^2 =

Vedclass · Accepted Answer

$9.240$

Vedclass · Answer

(C) Given: Radius $(r)$ = $21 \,cm$,Slant height $(l)$ = $29 \,cm$.First,find the height $(h)$ of the cone using the relation $l^2 = r^2 + h^2$.$h^2 = l^2 - r^2 = 29^2 - 21^2 = 841 - 441 = 400$.$h = \sqrt{400} = 20 \,cm$.The volume $(V)$ of a cone is given by $V = \frac{1}{3} \pi r^2 h$.$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 21 	imes 21 	imes 20 = 22 	imes 3 	imes 7 	imes 20 = 9240 \,cm^3$.Since $1000 \,cm^3 = 1 \,litre$,the capacity is $9240 / 1000 = 9.240 \,litres$.

The radius and slant height of a conical vessel are $21 \,cm$ and $29 \,cm$ respectively. What is its capacity in litres?

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