The radioactivity of a certain radioactive el | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The radioactive decay law is given by $\frac{N}{N_0} = \left(\frac{1}{2}\right)^n$,where $n$ is the number of half-lives.Given $\frac{N}{N_0} = \f

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) The radioactive decay law is given by $\frac{N}{N_0} = \left(\frac{1}{2}\right)^n$,where $n$ is the number of half-lives.Given $\frac{N}{N_0} = \frac{1}{64}$.So,$\frac{1}{64} = \left(\frac{1}{2}\right)^n$.Since $64 = 2^6$,we have $\left(\frac{1}{2}\right)^6 = \left(\frac{1}{2}\right)^n$,which implies $n = 6$.The total time $t = 30$ seconds.The number of half-lives $n = \frac{t}{T_{1/2}}$,where $T_{1/2}$ is the half-life.Therefore,$6 = \frac{30}{T_{1/2}}$.$T_{1/2} = \frac{30}{6} = 5$ seconds.

The radioactivity of a certain radioactive element drops to $\frac{1}{64}$ of its initial value in $30$ seconds. Its half-life is ............. seconds.

Similar Questions

The plot of the number $(N)$ of undecayed atoms versus activity $(A)$ of a radioactive substance is

Two radioactive materials $X_1$ and $X_2$ have decay constants $10 \lambda$ and $\lambda$ respectively. If initially they have the same number of nuclei,then the ratio of the number of nuclei of $X_1$ to that of $X_2$ will be $1 / e$ after a time:

The graph shows the $\log$ of activity $\log R$ of a radioactive material as a function of time $t$ in minutes. The half-life (in minutes) for the decay is closest to

The sample of a radioactive substance has $10^6$ nuclei. Its half-life is $20 \, s$. The number of nuclei that will be left after $10 \, s$ is nearly ...... $\times 10^5$.

If the half-life of a radioactive sample is $10\, hours$,its mean life is .......... $hours$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module