The radii of F, F^{-}, O and O^{2-} are in th | vedclass

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Question

(A) The size of an atom or ion depends on the effective nuclear charge and the number of shells.For isoelectronic species $(O^{2-}, F^{-})$,the specie

Vedclass · Accepted Answer

$O^{2-} > F^{-} > O > F$

Vedclass · Answer

(A) The size of an atom or ion depends on the effective nuclear charge and the number of shells.For isoelectronic species $(O^{2-}, F^{-})$,the species with the lower nuclear charge has a larger radius. Since $O$ $(Z=8)$ has a lower nuclear charge than $F$ $(Z=9)$,$O^{2-}$ is larger than $F^{-}$.Comparing neutral atoms,$O$ $(Z=8)$ is larger than $F$ $(Z=9)$ due to the decrease in atomic radius across a period.Furthermore,an anion is always larger than its parent neutral atom due to increased inter-electronic repulsion and decreased effective nuclear charge per electron.Therefore,the correct order of radii is $O^{2-} > F^{-} > O > F$.Hence,option $A$ is correct.

The radii of $F, F^{-}, O$ and $O^{2-}$ are in the order of :-

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