(A) The given quantum numbers $n = 2, l = 0, m = 0, s = +\frac{1}{2}$ correspond to the $2s^1$ orbital.This indicates that the outermost electron is i

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(A) The given quantum numbers $n = 2, l = 0, m = 0, s = +\frac{1}{2}$ correspond to the $2s^1$ orbital.This indicates that the outermost electron is in the $2s$ subshell.The electronic configuration of the element is $1s^2, 2s^1$.Since the total number of electrons is $3$,the atomic number $Z = 3$,which corresponds to Lithium $(Li)$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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The quantum numbers for the outermost electron of an element are given as $n = 2, l = 0, m = 0, s = +\frac{1}{2}$. The element is

A
Lithium
B
Beryllium
C
Hydrogen
D
Boron

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

As per the modern periodic law,the physical and chemical properties of elements are periodic functions of their

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For an electron with quantum numbers $s = +1/2$ and $m_l = -1$,which of the following orbitals is not possible?

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An electron in the $5d$ orbital can be represented by the following $(n, l, m_l)$ values:

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In a potassium atom,the electronic energy levels are in the following order:

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The maximum number of electrons which each sub-shell can occupy is

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The quantum numbers for the outermost electron of an element are given as $n = 2, l = 0, m = 0, s = +\frac{1}{2}$. The element is

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As per the modern periodic law,the physical and chemical properties of elements are periodic functions of their

For an electron with quantum numbers $s = +1/2$ and $m_l = -1$,which of the following orbitals is not possible?

An electron in the $5d$ orbital can be represented by the following $(n, l, m_l)$ values:

In a potassium atom,the electronic energy levels are in the following order:

The maximum number of electrons which each sub-shell can occupy is

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