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(A) To electrolyze $1 \ mol$ of each metal ion,the amount of electricity required is equal to the charge (valency) of the metal ion.For $ZnSO_{4}$,the

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$2: 3: 1$

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(A) To electrolyze $1 \ mol$ of each metal ion,the amount of electricity required is equal to the charge (valency) of the metal ion.For $ZnSO_{4}$,the reaction is: $Zn^{2+} + 2e^{-} \rightarrow Zn$. Thus,$2 \ F$ of electricity is required.For $AlCl_{3}$,the reaction is: $Al^{3+} + 3e^{-} \rightarrow Al$. Thus,$3 \ F$ of electricity is required.For $AgNO_{3}$,the reaction is: $Ag^{+} + e^{-} \rightarrow Ag$. Thus,$1 \ F$ of electricity is required.Therefore,the ratio of electricity required is $2: 3: 1$.

The quantity of electricity needed to separately electrolyze $1 \ M$ solution of $ZnSO_{4}$,$AlCl_{3}$ and $AgNO_{3}$ completely is in the ratio of

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