The quantity of charge that will be transferred by a current flow of $20 \text{ A}$ over a period of $1 \text{ hour } 30 \text{ minutes}$ is:
- A$10.8 \times 10^{3} \text{ C}$
- B$10.8 \times 10^{4} \text{ C}$
- C$5.4 \times 10^{3} \text{ C}$
- D$1.8 \times 10^{4} \text{ C}$
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