The products formed in the following reaction | vedclass

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(D) The reaction sequence is as follows:$1$. $Nitrobenzene$ reacts with $Br_2$ in $AcOH$ to undergo electrophilic aromatic substitution,forming $m-bro

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(D) The reaction sequence is as follows:$1$. $Nitrobenzene$ reacts with $Br_2$ in $AcOH$ to undergo electrophilic aromatic substitution,forming $m-bromonitrobenzene$ (since $-NO_2$ is a meta-directing group).$2$. Reduction of $m-bromonitrobenzene$ with $Sn/HCl$ yields $m-bromoaniline$.$3$. Treatment of $m-bromoaniline$ with $NaNO_2/HCl$ at $273-278 \ K$ results in diazotization,forming $m-bromobenzenediazonium \ chloride$.$4$. Finally,reaction with ethanol $(C_2H_5OH)$ reduces the diazonium salt to $bromobenzene$ (specifically $m-bromobenzene$ in this context,which is simply $bromobenzene$ as the bromine position is fixed) and ethanol is oxidized to acetaldehyde $(CH_3CHO)$.Thus,the final products are $bromobenzene$ and $CH_3CHO$.

The products formed in the following reaction sequence are:

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