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Question

(B) The reaction involves the acid-catalyzed alkylation of an alkene (isobutylene) with an alkane (isobutane). $1$. The $H^+$ ion protonates the isobu

Vedclass · Accepted Answer

$(CH_3)_2CH-CH_2-C(CH_3)_3$

Vedclass · Answer

(B) The reaction involves the acid-catalyzed alkylation of an alkene (isobutylene) with an alkane (isobutane). $1$. The $H^+$ ion protonates the isobutylene to form a stable tert-butyl carbocation: $(CH_3)_2C=CH_2 + H^+ \rightarrow (CH_3)_3C^+$. $2$. This carbocation then attacks another molecule of isobutylene to form a larger carbocation: $(CH_3)_3C^+ + (CH_3)_2C=CH_2 \rightarrow (CH_3)_3C-CH_2-C^+(CH_3)_2$. $3$. This new carbocation then abstracts a hydride ion from a molecule of isobutane: $(CH_3)_3C-CH_2-C^+(CH_3)_2 + (CH_3)_3CH \rightarrow (CH_3)_3C-CH_2-CH(CH_3)_2 + (CH_3)_3C^+$. The final product is $2,2,4$-trimethylpentane,which is $(CH_3)_3C-CH_2-CH(CH_3)_2$.

The products formed in the following reaction are:

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