The products X and Y in the following reactio | vedclass

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(B) $1$. The reaction of nitrobenzene with $Sn/HCl$ is a reduction reaction that converts the nitro group $(-NO_2)$ into an amino group $(-NH_2)$,form

Vedclass · Accepted Answer

$X$: Aniline,$Y$: Bromobenzene

Vedclass · Answer

(B) $1$. The reaction of nitrobenzene with $Sn/HCl$ is a reduction reaction that converts the nitro group $(-NO_2)$ into an amino group $(-NH_2)$,forming aniline $(X)$.$2$. Aniline reacts with $NaNO_2/HCl$ at low temperatures $(0-5 \ ^\circ C)$ to undergo diazotization,forming benzenediazonium chloride.$3$. The subsequent reaction with $CuBr$ (Sandmeyer reaction) replaces the diazonium group with a bromine atom,resulting in the formation of bromobenzene $(Y)$.

The products $X$ and $Y$ in the following reaction sequence are:

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