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(B) The reaction of benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$ with hypophosphorous acid $(H_3PO_2)$ in the presence of ethanol acts as a reducing

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benzene

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(B) The reaction of benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$ with hypophosphorous acid $(H_3PO_2)$ in the presence of ethanol acts as a reducing agent. This reaction results in the reduction of the diazonium group to a hydrogen atom,yielding benzene $(C_6H_6)$ as the major product. The reaction is: $C_6H_5N_2^+Cl^- + H_3PO_2 + H_2O \rightarrow C_6H_6 + N_2 + H_3PO_3 + HCl$ Therefore,the correct option is $B$.

The product of the following reaction is:
$C_6H_5N_2^+Cl^-$ $\xrightarrow{H_3PO_2 / \text{ethanol}}$ ?

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The product of the following reaction is: $C_6H_5N_2^+Cl^-$ $\xrightarrow{H_3PO_2 / \text{ethanol}}$ ?