The product obtained from the following seque | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: The reaction of propyne $(CH_3-C\equiv CH)$ with $HgSO_4$ and $H_2SO_4$ is a hydration reaction following Markovnikov's rule,which yield

Vedclass · Accepted Answer

$2-$propanol

Vedclass · Answer

(B) Step $1$: The reaction of propyne $(CH_3-C\equiv CH)$ with $HgSO_4$ and $H_2SO_4$ is a hydration reaction following Markovnikov's rule,which yields acetone $(CH_3-CO-CH_3)$ as product $A$.Step $2$: The reduction of acetone $(CH_3-CO-CH_3)$ with $NaBH_4$ reduces the ketone group to a secondary alcohol,yielding $2-$propanol $(CH_3-CH(OH)-CH_3)$ as product $B$.

The product obtained from the following sequence of reactions is
$CH_3-C\equiv CH$ $\xrightarrow{HgSO_4, H_2SO_4} A$ $\xrightarrow{NaBH_4} B$

Similar Questions

Reductive amination of $A$ forms :
$A$ :

Pyrolysis of acetone gives $CH_2=C=O$ called

Which of the following reactions converts $Acetone$ into a hydrocarbon having the same number of carbon atoms?

Identify the products $(A)$ and $(B)$ from the given structures $P, Q, R$.

Which of the following compounds is not formed in the iodoform reaction of acetone?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The product obtained from the following sequence of reactions is$CH_3-C\equiv CH$ $\xrightarrow{HgSO_4, H_2SO_4} A$ $\xrightarrow{NaBH_4} B$