The product formed in the following multistep | vedclass

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(B) Step $1$: Hydroboration-oxidation of propene $(CH_3-CH=CH_2)$ with $B_2H_6$ followed by $H_2O_2, NaOH$ gives propan$-1-$ol $(CH_3-CH_2-CH_2-OH)$.S

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$CH_3-CH_2-CH(OH)-CH_3$

Vedclass · Answer

(B) Step $1$: Hydroboration-oxidation of propene $(CH_3-CH=CH_2)$ with $B_2H_6$ followed by $H_2O_2, NaOH$ gives propan$-1-$ol $(CH_3-CH_2-CH_2-OH)$.Step $2$: Oxidation of propan$-1-$ol with $PCC$ (Pyridinium chlorochromate) gives propanal $(CH_3-CH_2-CHO)$.Step $3$: Reaction of propanal with methylmagnesium bromide $(CH_3MgBr)$ followed by acidic workup gives butan$-2-$ol $(CH_3-CH_2-CH(OH)-CH_3)$.

The product formed in the following multistep reaction is:

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