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(D) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols but does not reduce

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(D) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols but does not reduce esters,carboxylic acids,or amides under normal conditions. In the given substrate,there is a ketone group and an ester group $(-COOCH_3)$. Therefore,$NaBH_4$ will selectively reduce the ketone group to a secondary alcohol $(-CHOH)$ while leaving the ester group unaffected. The final product is a cyclohexane ring with an $-OH$ group,a $-CH_2-COOCH_3$ group,and a $-CH_3$ group.

The product formed in the following chemical reaction is :

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