The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

An organic compound having molecular formula $C_2H_6O$ undergoes oxidation with $K_2Cr_2O_7 / H_2SO_4$ to produce $X$ which contains $40\,\%$ carbon,$6.7\,\%$ hydrogen and $53.3\,\%$ oxygen. The molecular formula of the compound $X$ is

Match the reactions given in Column-$I$ with the appropriate reagents in Column-$II$.
| Column-$I$ (Reaction) | Column-$II$ (Reagent) |
| :--- | :--- |
| $(A)$ $2CH_3COOH \rightarrow (CH_3CO)_2O$ | $(i)$ $(I) NH_3, (II) \Delta, -H_2O$ |
| $(B)$ Phthalic acid $\rightarrow$ Phthalamide | $(ii)$ $(I) Br_2 / \text{red phosphorous}, (II) H_2O$ |
| $(C)$ $CH_3CH_2COOH \rightarrow CH_3CHBrCOOH$ | $(iii)$ $Br_2 / FeBr_3$ |
| $(D)$ Benzoic acid $\rightarrow$ $m$-Bromobenzoic acid | $(iv)$ $H^+, \Delta \text{ OR } P_2O_5, \Delta$ |

The correct order of acidity for the following compounds is:

Give the expected product of the following reaction.

In the given reaction,reagents '$X$' and '$Y$' respectively are: