The principle of 'parallax' is used in the determination of distances of very distant stars. The baseline $AB$ is the line joining the Earth's two locations six months apart in its orbit around the Sun. That is,the baseline is about the diameter of the Earth's orbit $\approx 3 \times 10^{11} \; m$. However,even the nearest stars are so distant that with such a long baseline,they show parallax only of the order of $1''$ (second of arc) or so. $A$ parsec is a convenient unit of length on the astronomical scale. It is the distance of an object that will show a parallax of $1''$ (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres?

  • A
    $1 \; \text{parsec} \approx 1.6 \times 10^{11} \; m$
  • B
    $1 \; \text{parsec} \approx 9.3 \times 10^{20} \; m$
  • C
    $1 \; \text{parsec} \approx 6.2 \times 10^{12} \; m$
  • D
    $1 \; \text{parsec} \approx 3.09 \times 10^{16} \; m$

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Similar Questions

It is a well-known fact that during a total solar eclipse,the disk of the Moon almost completely covers the disk of the Sun. From this fact and the information given below,determine the approximate diameter of the Moon.
Distance of the Moon from the Earth $= 3.84 \times 10^{8} \; m$
Distance of the Sun from the Earth $= 1.496 \times 10^{11} \; m$
Diameter of the Sun $= 1.39 \times 10^{9} \; m$

The moon is observed from two diametrically opposite points $A$ and $B$ on Earth. The angle $\theta$ subtended at the moon by the two directions of observation is $1^{\circ} 54^{\prime}$. Given the diameter of the Earth to be about $1.276 \times 10^{7} \; m$,compute the distance of the moon from the Earth.

Accuracy of measurement of a physical quantity depends on which factors?

Match List-$I$ (Event) with List-$II$ (Order of the time interval for happening of the event) and select the correct option from the options given below the lists:
List-$I$ List-$II$
$(1)$ Rotation period of earth $(i)$ $10^5\, s$
$(2)$ Revolution period of earth $(ii)$ $10^7\, s$
$(3)$ Period of light wave $(iii)$ $10^{-15}\, s$
$(4)$ Period of sound wave $(iv)$ $10^{-3}\, s$

Precise measurements of physical quantities are a need of science. For example,to ascertain the speed of an aircraft,one must have an accurate method to find its positions at closely separated instants of time. This was the actual motivation behind the discovery of radar in World War $II$. Think of different examples in modern science where precise measurements of length,time,mass,etc.,are needed. Also,wherever you can,give a quantitative idea of the precision needed.

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