The principal organic product formed in the reaction given below is
$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$

  • A
    $CH_3-CHBr(CH_2)_8COOH$
  • B
    $CH_2 = CH(CH_2)_8COBr$
  • C
    $BrCH_2-CH_2(CH_2)_8COOH$
  • D
    $CH_2 = CH(CH_2)_7CHBrCOOH$

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Similar Questions

Assertion $(A)$: Propene on addition with hydrogen bromide in the presence of peroxide gives $1-$bromopropane as the major product.
Reason $(R)$: $1-$bromopropane is the major product because it is formed through the stable carbocation.

Identify the correct stability order of the following alkenes:
$I) (CH_3)_2C=C(CH_3)_2$
$II) (CH_3)_2C=CH_2$
$III) (CH_3)_2C=CHCH_3$

Given below are two statements.
Statement $I :$ The presence of weaker $\pi$-bonds makes alkenes less stable than alkanes.
Statement $II :$ The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements,choose the correct answer from the options given below.

Statement-$I$ :- Ozonolysis reaction is used to locate the position of a double bond in an alkene.
Statement-$II$ :- When $but-1-ene$ and $but-2-ene$ are subjected to ozonolysis separately,both yield the same product.
In the light of the above statements,select the correct option.

Identify $A$ and $B$ in the following reaction:
Propene $\xrightarrow{\text{HBr (Benzoyl peroxide)}}$ $A$ (Major product)
Propene $\xrightarrow{\text{HI}}$ $B$ (Major product)

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