The present population of a town is 26010. It | vedclass

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(A) Let the population two years ago be $P$.The population increases at a rate of $2\%$ per annum.The formula for population after $n$ years is $A = P

Vedclass · Accepted Answer

$25000$

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(A) Let the population two years ago be $P$.The population increases at a rate of $2\%$ per annum.The formula for population after $n$ years is $A = P(1 + \frac{r}{100})^n$.Given $A = 26010$,$r = 2$,and $n = 2$.$26010 = P(1 + \frac{2}{100})^2$$26010 = P(1 + 0.02)^2$$26010 = P(1.02)^2$$26010 = P(1.0404)$$P = \frac{26010}{1.0404}$$P = 25000$.Therefore,the population of the town two years ago was $25000$.

The present population of a town is $26010$. It increases annually at the rate of $2\%$. What was the population of the town two years ago?

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