The potential energy U between two molecules | vedclass

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(D) The force $F$ between two molecules is related to the potential energy $U$ by the relation $F = -\frac{dU}{dx}$.This means the force is the negati

Vedclass · Accepted Answer

Repulsive,zero,attractive

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(D) The force $F$ between two molecules is related to the potential energy $U$ by the relation $F = -\frac{dU}{dx}$.This means the force is the negative of the slope of the $U-x$ graph.At point $A$ $(x = 0.6 \mathring{A})$,the slope $\frac{dU}{dx}$ is negative,so $F = -(	ext{negative}) = 	ext{positive}$,which corresponds to a repulsive force.At point $B$ $(x = 1.2 \mathring{A})$,the curve has a minimum,so the slope $\frac{dU}{dx} = 0$,which means the force $F = 0$.At point $C$ $(x = 1.8 \mathring{A})$,the slope $\frac{dU}{dx}$ is positive,so $F = -(	ext{positive}) = 	ext{negative}$,which corresponds to an attractive force.Therefore,the forces at $A, B, C$ are repulsive,zero,and attractive respectively.

The potential energy $U$ between two molecules as a function of distance $x$ between them is shown. $A, B, C$ are points for which $x = 0.6 \mathring{A}, 1.2 \mathring{A}, 1.8 \mathring{A}$ respectively. At $A, B, C$,the force between the two molecules is:

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