The potential difference between A and B in t | vedclass

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(D) To find the potential difference between $A$ and $B$, we apply Kirchhoff's Voltage Law $(KVL)$ along the path from $A$ to $B$.Starting from point

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(D) To find the potential difference between $A$ and $B$, we apply Kirchhoff's Voltage Law $(KVL)$ along the path from $A$ to $B$.Starting from point $A$, the potential is $V_A$.The current $I = 2 \, A$ flows through the circuit.The potential drop across the $6 \, \Omega$ resistor is $V_R = I 	imes R = 2 \, A 	imes 6 \, \Omega = 12 \, V$.Moving from $A$ to $B$:$V_A - (I 	imes 6 \, \Omega) - 12 \, V - (I 	imes 9 \, \Omega) + 4 \, V - (I 	imes 5 \, \Omega) = V_B$$V_A - 12 - 12 - 18 + 4 - 10 = V_B$$V_A - V_B = 12 + 12 + 18 - 4 + 10$$V_A - V_B = 48 \, V$.

The potential difference between $A$ and $B$ in the figure is ................... $V$.

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