The position of a particle moving in the xy- | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{x}=3 \mathrm{t}^{2}-6 \mathrm{t} \quad \mathrm{y}=\mathrm{t}^{2}-2 \mathrm{t}$

$\mathrm{v}_{\mathrm{x}}=\frac{\mathrm{dx}}{\mathrm{dt}}=6

Vedclass · Accepted Answer

The velocity of the particle is zero at $t = 1\, second$

Vedclass · Answer

$\mathrm{x}=3 \mathrm{t}^{2}-6 \mathrm{t} \quad \mathrm{y}=\mathrm{t}^{2}-2 \mathrm{t}$

$\mathrm{v}_{\mathrm{x}}=\frac{\mathrm{dx}}{\mathrm{dt}}=6 \mathrm{t}-6 \quad \mathrm{v}_{\mathrm{y}}=\frac{\mathrm{dy}}{\mathrm{dt}}=2 \mathrm{t}-2$

at $t=1 \sec \rightarrow v_{x}=0$ and $v_{y}=0$

hence $\quad v=\sqrt{v_{x}^{2}+v_{y}^{2}}=0$

The position of a particle moving in the $xy-$ plane at any time $t$ is given by $x = (3t^2 -6t)\, metres$, $y = (t^2 -2t)\,metres$. Select the correct statement about the moving particle from the following

Similar Questions

A mosquito is moving with a velocity $\overrightarrow{ v }=0.5 t ^{2} \hat{ i }+3 t \hat{ j }+9 \hat{ k }\, m / s$ and accelerating in uniform conditions. What will be the direction of mosquito after $2 \,s$ ?

The graph of position $x$ versus time $t$ represents the motion of a particle. If $b$ and $c$ are both positive constants, which of the following expressions best describes the acceleration $a$ of the particle?

Which two motions are considered to be combined for motion in plane ?

A particle moves in east direction with $15 \,m/sec$. for $2\, sec$ then moves northward with $5\, m/sec$. for $8 \,sec$. then average velocity of the particle is

The co-ordinates of a particle moving in $x-y$ plane are given by : $\mathrm{x}=2+4 \mathrm{t}, \mathrm{y}=3 \mathrm{t}+8 \mathrm{t}^2 .$ The motion of the particle is :