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(B) Given that,the present population $P = 370440$,the rate of increase $R = 5 \%$,and the time $n = 3$ years.Using the formula for population $n$ yea

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$3.2$

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(B) Given that,the present population $P = 370440$,the rate of increase $R = 5 \%$,and the time $n = 3$ years.Using the formula for population $n$ years ago:$	ext{Population} = \frac{P}{(1 + \frac{R}{100})^n}$Substituting the values:$	ext{Population} = \frac{370440}{(1 + \frac{5}{100})^3} = \frac{370440}{(1.05)^3} = \frac{370440}{(\frac{21}{20})^3}$$= \frac{370440 	imes 20 	imes 20 	imes 20}{21 	imes 21 	imes 21}$$= \frac{370440 	imes 8000}{9261}$$= 40 	imes 8000 = 320000$Since $320000$ is equal to $3.2$ lakh,the population $3$ years ago was $3.2$ lakh.

The population of a city increases at the rate of $5 \%$ $p.a.$ If the present population of the city is $370440$,then what was its population (in $lakh$) $3$ years ago?

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