The polarising angle for a transparent medium | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Brewster's Law,the refractive index $\mu$ of a transparent medium is given by $\mu = 	an 	heta$,where $	heta$ is the polarising an

Vedclass · Accepted Answer

$	heta = \cot^{-1}\left(\frac{V}{c}ight)$

Vedclass · Answer

(C) According to Brewster's Law,the refractive index $\mu$ of a transparent medium is given by $\mu = 	an 	heta$,where $	heta$ is the polarising angle.We also know that the refractive index $\mu$ is defined as the ratio of the speed of light in vacuum $(c)$ to the speed of light in the medium $(V)$:$\mu = \frac{c}{V}$Equating the two expressions for $\mu$:$	an 	heta = \frac{c}{V}$Taking the reciprocal on both sides:$\cot 	heta = \frac{V}{c}$Therefore,the relation between $	heta$ and $V$ is:$	heta = \cot^{-1}\left(\frac{V}{c}ight)$

The polarising angle for a transparent medium is $\theta$ and $V$ is the speed of light in that medium. The relation between $\theta$ and $V$ is (where $c$ is the velocity of light in vacuum):

Similar Questions

What is the Brewster angle for air to glass transition (in $^{\circ}$)? (Refractive index of glass $= 1.5.)$

$A$ ray of light is incident at a polarising angle such that its deviation is $24^{\circ}$. Then the angle of incidence is: (in $^{\circ}$)

An unpolarized light is incident from air on the boundary of a denser medium having refractive index $\mu$ at polarizing angle $i_p$. Which of the following is correct?

Let the speed of light in a medium be $V$ and the polarising angle be $i_p$. If $C$ is the speed of light in vacuum,what is the relation between them?

The refractive index of a material is equal to the tangent of the polarising angle. This is called:

Vedclass Test Series

Exam Paper Generator

Online Exam Module