(B) Let the point on the $y$-axis be $P(0, y)$.Since $P$ is equidistant from $A(3, 2)$ and $B(-1, 3)$,we have $PA^2 = PB^2$.$(0 - 3)^2 + (y - 2)^2 = (

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(B) Let the point on the $y$-axis be $P(0, y)$.Since $P$ is equidistant from $A(3, 2)$ and $B(-1, 3)$,we have $PA^2 = PB^2$.$(0 - 3)^2 + (y - 2)^2 = (0 - (-1))^2 + (y - 3)^2$$9 + y^2 - 4y + 4 = 1 + y^2 - 6y + 9$$13 - 4y = 10 - 6y$$2y = -3$$y = -\frac{3}{2}$Therefore,the required point is $(0, -\frac{3}{2})$.

Class 11 Mathematics Straight Line System of co-ordinates, Distance between two points, Section formulae

Easy

The point on the $y$-axis equidistant from the points $(3, 2)$ and $(-1, 3)$ is

A
$(0, -3)$
B
$(0, -3/2)$
C
$(0, 3/2)$
D
$(0, 3)$

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Class 11

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Straight Line

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System of co-ordinates, Distance between two points, Section formulae

The distance between the points $(a \cos \alpha, a \sin \alpha)$ and $(a \cos \beta, a \sin \beta)$ is

Easy

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The straight line $3x + y = 9$ divides the line segment joining the points $(1, 3)$ and $(2, 7)$ in the ratio

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The points $A(1, 1)$,$B(-2, 7)$,and $C(3, -3)$ are . . . . . . .

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What is the distance between the points $(2, 15^{\circ})$ and $(1, 75^{\circ})$ in polar coordinates?

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What are the coordinates of the points of trisection of the line segment joining the points $(-3, -3)$ and $(6, 6)$?

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The point on the $y$-axis equidistant from the points $(3, 2)$ and $(-1, 3)$ is

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