The point of intersection of the diagonals of | vedclass

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(B) The sides of the rectangle are given by the lines $x=8, x=10, y=11$,and $y=12$. These lines form a rectangle with vertices at the intersection poi

Vedclass · Accepted Answer

$\left(9, \frac{23}{2}\right)$

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(B) The sides of the rectangle are given by the lines $x=8, x=10, y=11$,and $y=12$. These lines form a rectangle with vertices at the intersection points: $(8, 11), (10, 11), (10, 12)$,and $(8, 12)$. The diagonals of a rectangle intersect at the midpoint of either diagonal. Taking the diagonal connecting $(8, 11)$ and $(10, 12)$,the midpoint is calculated as: $M = \left(\frac{8+10}{2}, \frac{11+12}{2}\right) = \left(\frac{18}{2}, \frac{23}{2}\right) = \left(9, \frac{23}{2}\right)$. Thus,the point of intersection is $\left(9, \frac{23}{2}\right)$.

The point of intersection of the diagonals of the rectangle whose sides are contained in the lines $x=8, x=10, y=11$ and $y=12$ is

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