The plot of velocity (v) versus displacement | vedclass

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Question

(A) From the given graph,the amplitude $(A)$ is the maximum displacement,which is $A = 10 \, cm = 0.1 \, m$.The maximum velocity $(v_{max})$ is given

Vedclass · Accepted Answer

$\frac{\pi}{2} \, s$

Vedclass · Answer

(A) From the given graph,the amplitude $(A)$ is the maximum displacement,which is $A = 10 \, cm = 0.1 \, m$.The maximum velocity $(v_{max})$ is given by $v_{max} = A \omega = 0.4 \, m/s$.Substituting the value of $A$,we get $0.1 	imes \omega = 0.4$,which implies $\omega = 4 \, rad/s$.The time period $(T)$ of oscillation is given by $T = \frac{2 \pi}{\omega}$.Substituting $\omega = 4 \, rad/s$,we get $T = \frac{2 \pi}{4} = \frac{\pi}{2} \, s$.Therefore,the correct option is $(A)$.

The plot of velocity $(v)$ versus displacement $(x)$ of a particle executing simple harmonic motion is shown in the figure. The time period of oscillation of the particle is .........

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