The photon having 6000 mathring{A} wavelengt | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is

Vedclass · Accepted Answer

$3000 \ \mathring{A}$

Vedclass · Answer

(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength. Since $h$ and $c$ are constants,$E \propto \frac{1}{\lambda}$. Given $E_1 = E$ and $\lambda_1 = 6000 \ \mathring{A}$. For $E_2 = 2E$,we have $\frac{E_2}{E_1} = \frac{\lambda_1}{\lambda_2}$. Substituting the values: $\frac{2E}{E} = \frac{6000 \ \mathring{A}}{\lambda_2}$. $2 = \frac{6000 \ \mathring{A}}{\lambda_2}$. $\lambda_2 = \frac{6000 \ \mathring{A}}{2} = 3000 \ \mathring{A}$.

The photon having $6000 \ \mathring{A}$ wavelength has energy $E$. If the energy of photon is $2E$,find the wavelength of the photon.

Similar Questions

When $\alpha$-particles are sent through a thin metal foil,most of them go straight through the foil because (one or more are correct)

The magnitude of kinetic energy $(K.E.)$ of an electron in a Bohr orbit is equal to which of the following?

The ratio of the radius of the second orbit of $Li^{2+}$ to that of the third orbit of $Be^{3+}$ is:

On what factors does the magnitude of the velocity of an electron in an orbit depend?

The wavelength of a spectral line emitted by a hydrogen atom in the Lyman series is $\frac{16}{15 R} \ cm$. What is the value of $n_2$? $(R = \text{Rydberg constant})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module