The phase difference between two points separ | vedclass

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Question

(B) The relationship between phase difference $(\Delta \phi)$ and path difference $(\Delta x)$ is given by: $\Delta \phi = \frac{2\pi}{\lambda} 	imes

Vedclass · Accepted Answer

$384$

Vedclass · Answer

(B) The relationship between phase difference $(\Delta \phi)$ and path difference $(\Delta x)$ is given by: $\Delta \phi = \frac{2\pi}{\lambda} 	imes \Delta x$.Given: $\Delta \phi = \frac{\pi}{2}$,$\Delta x = 0.8 \ m$,and frequency $f = 120 \ Hz$.Substituting the values: $\frac{\pi}{2} = \frac{2\pi}{\lambda} 	imes 0.8$.Solving for wavelength $(\lambda)$: $\lambda = 4 	imes 0.8 = 3.2 \ m$.The velocity of the wave $(v)$ is given by $v = f 	imes \lambda$.$v = 120 	imes 3.2 = 384 \ m/s$.

The phase difference between two points separated by $0.8 \ m$ in a wave of frequency $120 \ Hz$ is $\frac{\pi}{2}$. The velocity of the wave is ..... $m/s$.

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