The phase difference between the voltage and the current in an $AC$ circuit is $\pi / 4$. If the frequency is $50 \ Hz$,then this phase difference will be equivalent to a time of:

The peak value of $220 \, V$ of $ac$ mains is ...... $V$.

One complete set of negative and positive values of alternating quantities is called

The current in a circuit varies with time as $I = 2 \sqrt{t}$. The $rms$ value of the current for the interval $t = 2 \, s$ to $t = 4 \, s$ is:

In an $ac$ circuit,the instantaneous voltage $e(t)$ and current $i(t)$ are given by $e(t) = 5[\cos \omega t + \sqrt{3} \sin \omega t] \ V$ and $i(t) = 5[\sin(\omega t + \frac{\pi}{4})] \ A$. Determine the phase relationship between voltage and current.

An $AC$ source rated $220\, V, 50\, Hz$ is connected to a resistor. The time taken by the current to change from its maximum value to the $rms$ value is: