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(B) Given: Perpendicular height $h = 4 \frac{2}{3} 	ext{ m} = \frac{14}{3} 	ext{ m}$.Base diameter $d = 6 	ext{ m}$,so radius $r = \frac{d}{2} = 3

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$4$

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(B) Given: Perpendicular height $h = 4 \frac{2}{3} 	ext{ m} = \frac{14}{3} 	ext{ m}$.Base diameter $d = 6 	ext{ m}$,so radius $r = \frac{d}{2} = 3 	ext{ m}$.The volume of a conical tent is given by $V = \frac{1}{3} \pi r^2 h$.Substituting the values: $V = \frac{1}{3} 	imes \frac{22}{7} 	imes (3)^2 	imes \frac{14}{3}$.$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 9 	imes \frac{14}{3} = 22 	imes 2 = 44 	ext{ m}^3$.Since $11$ persons sleep in the tent,the average volume of air per person is $\frac{	ext{Total Volume}}{	ext{Number of persons}} = \frac{44}{11} = 4 	ext{ m}^3$.

The perpendicular height of a conical tent is $4 \frac{2}{3} \text{ m}$ and the diameter of its base is $6 \text{ m}$. If $11$ persons can sleep in this tent,find how many average cubic meters $(m^3)$ of air each person gets?

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