The period of moon's rotation around the eart | vedclass

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(D) The time period $T$ of a satellite revolving around a planet is given by the formula: $T = 2\pi \sqrt{\frac{r^3}{GM}}$, where $r$ is the orbital r

Vedclass · Accepted Answer

$29$

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(D) The time period $T$ of a satellite revolving around a planet is given by the formula: $T = 2\pi \sqrt{\frac{r^3}{GM}}$, where $r$ is the orbital radius, $G$ is the universal gravitational constant, and $M$ is the mass of the planet (Earth). Note that the mass of the satellite (Moon) does not appear in this formula. Since the time period is independent of the mass of the satellite, changing the mass of the Moon will have no effect on its orbital period. Therefore, the period remains $29$ days.

The period of moon's rotation around the earth is nearly $29$ days. If moon's mass were $2$ fold, its present value and all other things remained unchanged, the period of moon's rotation would be nearly ......... $days$.

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