The perimeter of the base of a right circular | vedclass

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(B) The perimeter of the base of a right circular cone is given by $2 \pi r = 132 \, cm$.Using $\pi = \frac{22}{7}$,we have $2 	imes \frac{22}{7} 	i

Vedclass · Accepted Answer

$6336$

Vedclass · Answer

(B) The perimeter of the base of a right circular cone is given by $2 \pi r = 132 \, cm$.Using $\pi = \frac{22}{7}$,we have $2 	imes \frac{22}{7} 	imes r = 132$.$r = \frac{132 	imes 7}{44} = 21 \, cm$.The slant height $l$ is given by $l = \sqrt{h^2 + r^2} = \sqrt{72^2 + 21^2} = \sqrt{5184 + 441} = \sqrt{5625} = 75 \, cm$.The total surface area $(TSA)$ of the cone is $\pi r(l + r)$.$TSA = \frac{22}{7} 	imes 21 	imes (75 + 21) = 22 	imes 3 	imes 96 = 66 	imes 96 = 6336 \, cm^2$.

The perimeter of the base of a right circular cone is $132 \, cm$. If the height of the cone is $72 \, cm$,then what is the total surface area (in $cm^2$) of the cone?

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