The path difference between two interfering light waves meeting at a point on the screen is $\left(\frac{87}{2}\right) \lambda$. The band obtained at that point is

  • A
    $87^{\text{th}}$ bright band
  • B
    $44^{\text{th}}$ dark band
  • C
    $87^{\text{th}}$ dark band
  • D
    $44^{\text{th}}$ bright band

Explore More

Similar Questions

In Young's experiment,the separation between the $5^{\text{th}}$ maxima and the $3^{\text{rd}}$ minima is how many times the fringe width?

Explain Young's double-slit experiment,its experimental arrangement,and how it produces an interference pattern.

Electrons accelerated from rest by an electrostatic potential are collimated and sent through a Young's double slit experiment. The fringe width is $\omega$. If the accelerating potential is doubled,then the width is now close to ............. $\omega$.

In the $Young's$ double slit experiment,the intensity produced by each of the individual slits is $I_0$. The distance between the two slits is $2 \ mm$. The distance of the screen from the slits is $10 \ m$. The wavelength of light is $6000 \ \mathring{A}$. What is the intensity of light on the screen in front of one of the slits?

In Young's double slit experiment,a mica sheet of thickness $t$ and refractive index $\mu$ is introduced in the path of the ray from the first source $S_1$. By what distance will the fringe pattern be displaced?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo