(D) Given path difference $\Delta x = 3 \mu m = 3 \times 10^{-6} \text{ m}$.The wavelength $\lambda = 5000 \text{ Å} = 5000 \times 10^{-10} \text{ m}

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(D) Given path difference $\Delta x = 3 \mu m = 3 \times 10^{-6} \text{ m}$.The wavelength $\lambda = 5000 \text{ Å} = 5000 \times 10^{-10} \text{ m} = 5 \times 10^{-7} \text{ m}$.For constructive interference (bright band),the condition is $\Delta x = n \lambda$,where $n = 0, 1, 2, 3, \dots$.Substituting the values: $3 \times 10^{-6} = n \times (5 \times 10^{-7})$.$n = \frac{3 \times 10^{-6}}{5 \times 10^{-7}} = \frac{30}{5} = 6$.Since $n = 6$ is an integer,the point $Q$ corresponds to the $6^{\text{th}}$ bright band.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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The path difference between two identical light waves at a point $Q$ on the screen is $3 \mu m$. If the wavelength of the waves is $5000 \text{ Å}$,then at point $Q$ there is:

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$3^{\text{rd}}$ dark band
B
$4^{\text{th}}$ bright band
C
$5^{\text{th}}$ dark band
D
$6^{\text{th}}$ bright band

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Wave Optics

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Young's Double Slit Experiment (YDSE)

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The path difference between two identical light waves at a point $Q$ on the screen is $3 \mu m$. If the wavelength of the waves is $5000 \text{ Å}$,then at point $Q$ there is:

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