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(B) The correct answer is $B$. In an aqueous solution of $NaCl$,the ions present are $Na^+$,$Cl^-$,$H^+$,and $OH^-$.At the cathode,$H_2O$ is reduced i

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$NaCl$ in water

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(B) The correct answer is $B$. In an aqueous solution of $NaCl$,the ions present are $Na^+$,$Cl^-$,$H^+$,and $OH^-$.At the cathode,$H_2O$ is reduced in preference to $Na^+$ because the reduction potential of water is higher than that of $Na^+$.Cathode reaction: $2H_2O(l) + 2e^- 	o H_2(g) + 2OH^-(aq)$.At the anode,$Cl^-$ is oxidized to $Cl_2$ gas.Anode reaction: $2Cl^-(aq) 	o Cl_2(g) + 2e^-$.

The passage of current liberates $H_2$ at cathode and $Cl_2$ at anode. The solution is

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