The pair of species with similar shape is

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(A) To determine the shape of the species,we use the $VSEPR$ theory based on the number of bonding pairs and lone pairs of electrons.$1$. $PCl_3$ has

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$PCl_3, NH_3$

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(A) To determine the shape of the species,we use the $VSEPR$ theory based on the number of bonding pairs and lone pairs of electrons.$1$. $PCl_3$ has $3$ bond pairs and $1$ lone pair on $P$,resulting in a trigonal pyramidal shape. $NH_3$ also has $3$ bond pairs and $1$ lone pair on $N$,resulting in a trigonal pyramidal shape. Thus,they have similar shapes.$2$. $CF_4$ is tetrahedral ($4$ bond pairs,$0$ lone pairs),while $SF_4$ is see-saw shaped ($4$ bond pairs,$1$ lone pair).$3$. $PbCl_2$ is bent (angular) due to the presence of a lone pair on $Pb$,while $CO_2$ is linear.$4$. $PF_5$ is trigonal bipyramidal,while $IF_5$ is square pyramidal.Therefore,the correct pair is $PCl_3$ and $NH_3$.

List-$I$ Molecule/ion	List-$II$ Bond pair : lone pair (on the central atom)
$A. ICl_2^-$	$I. 4 : 2$
$B. H_2O$	$II. 4 : 1$
$C. SO_2$	$III. 2 : 3$
$D. XeF_4$	$IV. 2 : 2$

Similar Questions

Match the List-$I$ with List-$II$.

List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom)

$A. ICl_2^-$ $I. 4 : 2$

$B. H_2O$ $II. 4 : 1$

$C. SO_2$ $III. 2 : 3$

$D. XeF_4$ $IV. 2 : 2$

Choose the correct answer from the options given below:

The shape of a molecule of $NH_3$,in which the central atom contains a lone pair of electrons,is

In the following reaction,how do the $Cl-P-Cl$ bond angles change?
$PCl_5 \longrightarrow PCl_4^+ + Cl^-$

Which of the following hydrides has the largest bond angle?

Select the correct statement regarding the following change:
$NO_2^+ \to NO_2 \to NO_2^-$

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