The pair of molecules / ions with the same bo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the bond order,we use the formula: $	ext{Bond Order} = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of bonding electrons and $

Vedclass · Accepted Answer

$O_2, C_2$

Vedclass · Answer

(B) To determine the bond order,we use the formula: $	ext{Bond Order} = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.For $B_2$ ($10$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^1, \pi 2p_y^1$. Bond order = $\frac{1}{2} (6 - 4) = 1$.For $C_2$ ($12$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^2$. Bond order = $\frac{1}{2} (8 - 4) = 2$.For $O_2$ ($16$ electrons): Bond order = $2$.For $O_2^{+}$ ($15$ electrons): Bond order = $2.5$.For $O_2^{-}$ ($17$ electrons): Bond order = $1.5$.For $H_2^{+}$ ($1$ electron): Bond order = $0.5$.For $Li_2$ ($6$ electrons): Bond order = $1$.Re-evaluating the options:$A$: $B_2$ ($BO$=$1$),$C_2$ ($BO$=$2$)$B$: $O_2$ ($BO$=$2$),$C_2$ ($BO$=$2$)$C$: $O_2^{+}$ ($BO$=$2.5$),$O_2^{-}$ ($BO$=$1.5$)$D$: $H_2^{+}$ ($BO$=$0.5$),$Li_2$ ($BO$=$1$)The correct pair with the same bond order is $O_2$ and $C_2$.

List-$I$ (Molecule / ion)	List-$II$ (Bond order)
$1$. $NO$	$i$. $1.5$
$2$. $CO$	$ii$. $2.0$
$3$. $O_2^{-}$	$iii$. $2.5$
$4$. $O_2$	$iv$. $3.0$

The pair of molecules / ions with the same bond order value is

Similar Questions

Explain the linear combination of atomic orbitals $(LCAO)$ with a suitable example.

Match List-$I$ with List-$II$ and select the correct option:
List-$I$ (Molecule / ion) List-$II$ (Bond order)
$1$. $NO$ $i$. $1.5$
$2$. $CO$ $ii$. $2.0$
$3$. $O_2^{-}$ $iii$. $2.5$
$4$. $O_2$ $iv$. $3.0$

Which one of the following pairs of species have the same bond order?

Between $1s-1s$ and $1s-2s$ combinations,which one does not form a molecular orbital? Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module