The pair of lanthanoid ions which are diamagn | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) substance is diamagnetic if it has no unpaired electrons $(n = 0)$.Electronic configurations of the given ions:$Ce^{4+} \Rightarrow [Xe] 4f^0$ (No

Vedclass · Accepted Answer

$Ce^{4+}$ and $Yb^{2+}$

Vedclass · Answer

(D) substance is diamagnetic if it has no unpaired electrons $(n = 0)$.Electronic configurations of the given ions:$Ce^{4+} \Rightarrow [Xe] 4f^0$ (No unpaired electrons,diamagnetic)$Yb^{2+} \Rightarrow [Xe] 4f^{14}$ (All electrons paired,diamagnetic)$Ce^{3+} \Rightarrow [Xe] 4f^1$ (One unpaired electron,paramagnetic)$Eu^{2+} \Rightarrow [Xe] 4f^7$ (Seven unpaired electrons,paramagnetic)$Gd^{3+} \Rightarrow [Xe] 4f^7$ (Seven unpaired electrons,paramagnetic)$Eu^{3+} \Rightarrow [Xe] 4f^6$ (Six unpaired electrons,paramagnetic)$Pm^{3+} \Rightarrow [Xe] 4f^4$ (Four unpaired electrons,paramagnetic)$Sm^{3+} \Rightarrow [Xe] 4f^5$ (Five unpaired electrons,paramagnetic)Thus,the pair $Ce^{4+}$ and $Yb^{2+}$ is diamagnetic.

The pair of lanthanoid ions which are diamagnetic is

Similar Questions

Lanthanoid contraction is caused due to

What is the general electronic configuration of actinoids?

Which actinoid elements have a $5f^{14}$ electronic configuration in their atoms?

In the lanthanoid series,the basicity of lanthanoid hydroxides $Ln(OH)_3$:

Vedclass Test Series

Exam Paper Generator

Online Exam Module