The pair of atoms having the same number of n | vedclass

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(C) The number of neutrons in an atom is calculated as $N = A - Z$,where $A$ is the mass number and $Z$ is the atomic number.$A)$ $^{12}_{6}C$: $12 -

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$^{23}_{11}Na, ^{24}_{12}Mg$

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(C) The number of neutrons in an atom is calculated as $N = A - Z$,where $A$ is the mass number and $Z$ is the atomic number.$A)$ $^{12}_{6}C$: $12 - 6 = 6$ neutrons; $^{24}_{12}Mg$: $24 - 12 = 12$ neutrons.$B)$ $^{23}_{11}Na$: $23 - 11 = 12$ neutrons; $^{19}_{9}F$: $19 - 9 = 10$ neutrons.$C)$ $^{23}_{11}Na$: $23 - 11 = 12$ neutrons; $^{24}_{12}Mg$: $24 - 12 = 12$ neutrons.$D)$ $^{23}_{11}Na$: $23 - 11 = 12$ neutrons; $^{39}_{19}K$: $39 - 19 = 20$ neutrons.Since $^{23}_{11}Na$ and $^{24}_{12}Mg$ both have $12$ neutrons,option $C$ is correct.

The pair of atoms having the same number of neutrons is

Similar Questions

Give the relation between the following pairs of species:
$(i)$ $_{20}^{40}Ca$ and $_{19}^{40}K$
$(ii)$ $_{17}^{35}Cl$ and $_{17}^{37}Cl$
$(iii)$ $_{18}^{40}Ar$,$_{20}^{40}Ca$ and $_{19}^{40}K$
$(iv)$ $_{38}^{87}Sr$ and $_{38}^{90}Sr$

Which of the following is isoelectronic with a carbon atom?

The electronic configuration of a dipositive ion $M^{2+}$ is $2, 8, 14$ and its atomic mass is $56$. The number of neutrons in the nucleus would be :

Assertion : An atom is electrically neutral.
Reason : Atom contains equal number of protons and neutrons.

If $W$ is the mass number and $N$ is the atomic number of an element,then:

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