The oxidation states of P atom in POCl_3,H_3P | vedclass

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Question

(A) The correct option is $A$.Let the oxidation state of $P$ atom be $x$.$(I)$ For $POCl_3$: $x + 1(-2) + 3(-1) = 0 \implies x - 2 - 3 = 0 \implies x

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$+5, +3, +4$

Vedclass · Answer

(A) The correct option is $A$.Let the oxidation state of $P$ atom be $x$.$(I)$ For $POCl_3$: $x + 1(-2) + 3(-1) = 0 \implies x - 2 - 3 = 0 \implies x = +5$.$(II)$ For $H_3PO_3$: $3(1) + x + 3(-2) = 0 \implies 3 + x - 6 = 0 \implies x = +3$.$(III)$ For $H_4P_2O_6$: $4(1) + 2x + 6(-2) = 0 \implies 4 + 2x - 12 = 0 \implies 2x = 8 \implies x = +4$.Thus,the oxidation states are $+5, +3, +4$.

The oxidation states of $P$ atom in $POCl_3$,$H_3PO_3$ and $H_4P_2O_6$,respectively are

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