(C) Let the oxidation state of molybdenum be $x$.The complex is $[Mo_2O_4(C_2H_4)_2(H_2O_2)]^{2-}$.Oxidation state of $O$ is $-2$,$C_2H_4$ (ethene) is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Let the oxidation state of molybdenum be $x$.The complex is $[Mo_2O_4(C_2H_4)_2(H_2O_2)]^{2-}$.Oxidation state of $O$ is $-2$,$C_2H_4$ (ethene) is $0$,and $H_2O_2$ (hydrogen peroxide) is $0$ in this coordination environment.$2x + 4(-2) + 2(0) + 0 = -2$$2x - 8 = -2$$2x = 6$$x = +3$