The oxidation state of cobalt in the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall char

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall charge of the molecule $Co_2(CO)_8$ is $0$,we can calculate the oxidation state of $Co$ as follows:Let the oxidation state of $Co$ be $x$.$2x + 8(0) = 0$$2x = 0$$x = 0$Therefore,the oxidation state of cobalt in the molecule is $0$.

The oxidation state of cobalt in the following molecule is

Similar Questions

Finely divided iron combines with $CO$ to give

The number of bridging $CO$ ligand$(s)$ and $Co-Co$ bond$(s)$ in $Co_2(CO)_8$ respectively are

In $Fe(CO)_5$,the $Fe-C$ bond has

The $V-C$ distance in $[V(CO)_6]$ and $[V(CO)_6]^-$ are respectively (in $pm$):

Which of the following carbonyls will have the strongest $C-O$ bond?

Vedclass Test Series

Exam Paper Generator

Online Exam Module